Page 19 - ePD310_技術高中數學C第二冊學習講義含解析本_課本PDF

Chapter 1 式的運算 13

1-1 學習成效驗收 解析 P.4、5

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1. Շࡈεධό f (x) = x + 4x - 2 ʿ g(x) = ax + bx + cx + ddʊٝ f (11) = g(11)d
f (13) = g(13)df (17) = g(17)df (19) = g(19)dӋ adbdcddj f
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2. ண f (x) = 2x - 5x + 3x + 4x - 2 = a(x + 1) + b(x + 1) + c(x + 1) + d(x + 1) + ed༊Ӌj
Ȅ aebecedee ٙ࠽ f
ȅ f (-0.99) ٙ࠽ՑʃᅰᓃܝୋɚЗ€ୋɧЗ̬વʞɝ f
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3. ண f (x) = 3x + x + 2x + 4eg (x) = x + 5x - x - 7dӋ f (x) + g (x) = f
ၾ f (x) - g (x) = f

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4. εධό f (x) = 16x - 24x - 20x + 32dӋj
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Ȅ ߰ f (x) = a(2x - 3) + b(2x - 3) + c(2x - 3) + ddӋ adbdcddj f
ȅ Ӌ f (1.52) ٙ࠽€̬વʞɝՑʃᅰᓃܝୋɚЗ f

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5. ߰ 2x - 3x + ax + b ৰ˸ x - 2x - 3 ٙቱόމ 12x - 2dӋ a ၾ bj f
6. л͜ၝΥৰجdӋɨΐ΢ᕚٙਠόʿቱόj

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Ȅ (3x - 4x + 5) ÷ (x + 1) f
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ȅ (x - 4x + 1) ÷ (x - 3) f
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7. ༊˸ၝΥৰجdӋ (x + x - 7x + 4) ÷ (x - 2) ٙਠό ʿቱό f

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8. f (x) މεධόd߰ f (x ) - 3xf (x) = -x + 2x + 7dӋ f (x) ٙהϞڷᅰձk f
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9. ண f (x) = ax + (b - 2)x - 7x + c + 1eg (x) = -x + dx - 3d߰ f (x) = g (x)dӋ aebece
d ٙ࠽ f

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10. ண f (x) = (a + 2)x + (b - 1)x + 4 + cd༊Աɨΐૢ΁dӋ aebec ʘ࠽j
Ȅ f (x) މɓϣεධόd˲࠯ධڷᅰމ 7d੬ᅰධމ -2d f

ȅ f (x) މཧεධόd f