Page 20 - ePD310_技術高中數學C第二冊學習講義含解析本_課本PDF

14 數學 C 第二冊

11. ʷᔊɨΐ΢όj

3
3
3
3
Ȅ -2x + 5x = fcȅ -2x - 5x = fc
5 3
4
4
Ȇ 3x × x = fc ȇ 3x ÷ x = f
2 5
2
2
3
12. ண f (x) = 2x - x + 8eg (x) = -x + 4x + 5x + 6dӋ 2f (x) - 3g (x) މ f
2
2
13. ண f (x) = x - 5x - 6eg (x) = 2x + x - 4d˸ʱᕎڷᅰجӋ f (x) × g (x) މ
f

14. ༊л͜࠱جʮόdਗ਼ɨΐεධό࢝කj
2
Ȅ (4x + 5y) = f
2
2
ȅ (x - 5y)(x + 5xy + 25y ) = f
2
Ȇ (x + 2y - 3) = f

2
2
15. Ӌ (4x - 1 - 3x )(5 + 2x - 7x) ٙ࠱ጐʕj
2
3
Ȅ x ٙڷᅰ iȅ x ٙڷᅰ f

2
2
3
16. ߰ x + ax + x + b ஗ x + 2x - 1 ዆ৰdӋ a ၾ b ΢މОk f
2
6
7
5
4
3
17. л͜ၝΥৰجdӋ˸ x - 4 ৰ 2x - 8x + x - 9x + 2x + 3x - 12x + 43 ٙਠόʿቱό
f
3
2
18. л͜ၝΥৰجdӋ˸ 2x + 1 ৰ 6x + x - 5x + 9 ٙਠόʿቱό f
19. л͜ၝΥৰجdӋɨΐ΢ᕚٙਠόʿቱόj
4
2
Ȅ ˸ x - 3 ৰ x - 4x + 1d f
4
3
2
ȅ ˸ 3x - 2 ৰ 3x - 5x - x + 8x - 4d f
f (x) 2x + 3
20. ߰ = x - 1 + 2 dۆ f (x) = k f
2
x + x + 1 x + x + 1