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6   數學 B  第三冊






                           1 - 1 學習成效驗收                                                                    解析 P.2



                    1.  ༆ɨΐ΢˙೻όj

                       Ȅ 5(4x + 1) + 2 = 4(5x - 1) + 11 & x =              f
                           1
                       ȅ   x + 1 = 4 & x =              f
                           2
                       Ȇ 3x = x & x =              f
                       ȇ 5 - 7x = - 5x - 1 & x =              f




                    2.  ༆ɨΐ΢˙೻όj
                       Ȅ x - 5 = x + 6 & x =             f
                       ȅ 3x = 3x - 4 & x =              f

                       Ȇ 4x + 5 = 4x + 5 & x =              f

                       ȇ 3x - 4 = 5 & x =              f



                    3.  ༆ɨΐ΢˙೻όj
                                  x    x
                       Ȅ x = 1 +   +   & x =               f
                                  2    4
                              15 - 4x
                       ȅ x -           = 2 & x =            f
                                  3
                       Ȇ (4x + 7) - x = (3x + 4) - 3 & x =             f



                    4.  ༆ɨΐ΢˙೻όj
                                  x    x
                       Ȅ x = 1 +   +   & x =               f
                                  3    9
                                  9 + x
                       ȅ - 2x +         = 3 & x =            f
                                    2
                       Ȇ 2x - 3[x - (1 + x)] = 13 + 2x & x =             f



                    5.  ༆ɨΐ΢ʔഃόdԨྡͪՉ༆j
                       Ȅ x + 2 > 8 &              fcȅ 5x < 12 &                 f

                       Ȇ - 3x > 9 &              fc ȇ 3x - 6 # 4x + 1 &                f



                    6.  ༆ʔഃό x $ 3x - 4 > - 2x + 1 &                 f



                    7.  ༆ʔഃό 3x - 3 < 9 # 4x + 1 &                 f
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